If the lines represented by the equations 3x y 5 and 6x 2y p are parallel then the value of p is

4

For which value[s] of p, will the lines represented by the following pair of linear equations be parallel

3x – y – 5 = 0

6x – 2y – p = 0


Two lines a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0 will be parallel if

Here, in given equations,

p 10

Therefore, p can take any real value other than 10.

Hence, option a is the correct answer.

Given pair of linear equations is

3x – y – 5 = 0  ......[i]

6x – 2y – p = 0   ......[ii]

On comparing with ax + by + c = 0 we get

We get,

a1 = 3, b1 = – 1, c1 = – 5

a2 = 6, b2 = – 2, c2 = – p

`a_1/a_2 = 3/6 = 1/2`

`b_1/b_2 = 1/2`

`c_1/c_2 = 5/p`

Since, the lines represented by these equations are parallel, then

`a_1/a_2 = b_1/b_2 ≠ c_1/c_2`

Taking last two parts, we get `1/2 ≠ 5/p`

So, p ≠ 10

Hence, the given pair of linear equations are parallel for all real values of p except 10.

Question 4 - CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at Nov. 1, 2019 by

For which value[s] of p, will the lines represented by the following pair of linear equations be parallel

  3x − y − 5 = 0

  6x −2y − p = 0

[a] all real values except 10  [b] 10  [c] 5/2  [d] 1/2

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Transcript

Question 4 For which value[s] of p, will the lines represented by the following pair of linear equations be parallel 3x − y − 5 = 0 6x − 2y − p = 0 [a] all real values except 10 [b] 10 [c] 5/2 [d] 1/2 Given lines 3x − y − 5 = 0 and 6x − 2y − p = 0 3x − y − 5 = 0 Comparing with a1x + b1y + c1 = 0 a1 = 3, b1 = –1, c1 = –5 6x − 2y − p = 0 Comparing with a2x + b2y + c2 = 0 a2 = 6, b2 = –2, c2 = –p Now, Since lines are parallel 𝑎_1/𝑎_2 = 𝑏_1/𝑏_2 ≠ 𝑐_1/𝑐_2 Comparing 𝑎_1/𝑎_2 = 𝑏_1/𝑏_2 ≠ 𝑐_1/𝑐_2 3/6=[−1]/[−2] ≠ [−5]/[−𝑝] 1/2=1/2 ≠ 5/𝑝 Therefore, 1/2 ≠ 5/𝑝 p ≠ 5 × 2 p ≠ 10 So, correct answer is [a] – all real values except 10

  1. Class 10
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  3. CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard

Find the value[s] of p in the following pair of equations: 3x y 5 = 0 and 6x 2y p = 0, if the lines represented by these equations are parallel. Maths Q&A

Solution

Step 1: Compute the ratios of coefficients.

Given: pair of linear equations is

3x-y- 5=06x-2y-p=0

On comparing the given equations with ax+by+c=0 , we get

a1=3, b1=-1,c1=-5a2=6,b2=-2,c2=- p

a1a2=36b1b2=12c1c2 =5p

Step 2: Compute the required value.

Since the lines represented by these equations are parallel.

Then the condition is:

a1a2=b1b2≠c1 c2

On considering the last two parts, we get

12≠5p⇒p≠10.

Hence, the given pair of linear equations are parallel for all real values of p except 10.


For what value of P will the lines 3x y 5 0 and 6x 2y p 0 are parallel?

3x – y – 5 = 0 and 6x – 2y – p = 0, if the lines represented by these equations are parallel. Find p. Hence, the given pair of linear equations are parallel for all real values of p except 10.

For what value of p lines are parallel?

∵p∈R−{10}, to represent parallel lines.

For what value of p Do the equation 3x 5y 7 and 2px 3y 1 represent intersecting lines?

For all values of p except 109, the given lines represents intersecting lines.

How do you prove that two lines are parallel equation?

Two lines are parallel if and only if their slopes are equal. The line 2x – 3y = 4 is in standard form. In general, a line in the form Ax + By = C has a slope of –A/B; therefore, the slope of line q must be –2/–3 = 2/3.

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