Đề bài - bài 2 trang 36 tài liệu dạy – học toán 9 tập 1

\[\begin{array}{l}a]\;\sqrt[3]{{64}} - \sqrt[3]{{ - 125}} - 2\sqrt[3]{{216}}\\ = \sqrt[3]{{{4^3}}} - \sqrt[3]{{{{\left[ { - 5} \right]}^3}}} - 2\sqrt[3]{{{6^3}}}\\ = 4 - \left[ { - 5} \right] - 2.6\\ = - 3.\end{array}\] \[\begin{array}{l}b]\;\sqrt[3]{{81}} + 3\sqrt[3]{{24}} - 2\sqrt[3]{{375}}\\ = \sqrt[3]{{{{3.3}^3}}} + 3\sqrt[3]{{{{3.2}^3}}} - 2\sqrt[3]{{{{3.5}^3}}}\\ = 3\sqrt[3]{3} + 3.2\sqrt[3]{3} - 2.5\sqrt[3]{3}\\ = - \sqrt[3]{3}.\end{array}\]

Đề bài

Tính :

a] \[\sqrt[3]{{64}} - \sqrt[3]{{ - 125}} - 2\sqrt[3]{{216}}\];

b] \[\sqrt[3]{{81}} + 3\sqrt[3]{{24}} - 2\sqrt[3]{{375}}\];

c] \[\dfrac{{\sqrt[3]{{135}}}}{{\sqrt[3]{5}}} - \sqrt[3]{{54}}.\sqrt[3]{4}\];

d] \[\sqrt[3]{{54x{y^3}}} - y\sqrt[3]{{128x}}\];

e] \[\sqrt {7 - 4\sqrt 3 } - \sqrt[3]{{26 + 15\sqrt 3 }}\].

Phương pháp giải - Xem chi tiết

+] Sử dụng công thức: \[\sqrt[3]{{ab}} = \sqrt[3]{a}.\sqrt[3]{b},\;\;\sqrt[3]{{\dfrac{a}{b}}} = \dfrac{{\sqrt[3]{a}}}{{\sqrt[3]{b}}}\;\;\left[ {b \ne 0} \right].\]

Lời giải chi tiết

\[\begin{array}{l}a]\;\sqrt[3]{{64}} - \sqrt[3]{{ - 125}} - 2\sqrt[3]{{216}}\\ = \sqrt[3]{{{4^3}}} - \sqrt[3]{{{{\left[ { - 5} \right]}^3}}} - 2\sqrt[3]{{{6^3}}}\\ = 4 - \left[ { - 5} \right] - 2.6\\ = - 3.\end{array}\] \[\begin{array}{l}b]\;\sqrt[3]{{81}} + 3\sqrt[3]{{24}} - 2\sqrt[3]{{375}}\\ = \sqrt[3]{{{{3.3}^3}}} + 3\sqrt[3]{{{{3.2}^3}}} - 2\sqrt[3]{{{{3.5}^3}}}\\ = 3\sqrt[3]{3} + 3.2\sqrt[3]{3} - 2.5\sqrt[3]{3}\\ = - \sqrt[3]{3}.\end{array}\]

\[\begin{array}{l}c]\;\dfrac{{\sqrt[3]{{135}}}}{{\sqrt[3]{5}}} - \sqrt[3]{{54}}.\sqrt[3]{4}\\ = \sqrt[3]{{\dfrac{{135}}{5}}} - \sqrt[3]{{54.4}}\\ = \sqrt[3]{{27}} - \sqrt[3]{{216}}\\ = \sqrt[3]{{{3^3}}} - \sqrt[3]{{{6^3}}}\\ = 3 - 6 = - 3.\end{array}\] \[\begin{array}{l}d]\;\sqrt[3]{{54x{y^3}}} - y\sqrt[3]{{128x}}\\ = \sqrt[3]{{{{2.3}^3}x{y^3}}} - y\sqrt[3]{{{{2.4}^3}x}}\\ = 3y\sqrt[3]{{2x}} - 4y\sqrt[3]{{2x}}\\ = - y\sqrt[3]{{2x}}\end{array}\]

\[e]\;\sqrt {7 - 4\sqrt 3 } - \sqrt[3]{{26 + 15\sqrt 3 }}\]

\[= \sqrt {4 - 2.2.\sqrt 3 + {{\left[ {\sqrt 3 } \right]}^2}} \]\[\; - \sqrt[3]{{{2^3} + {{3.2}^2}\sqrt 3 + 3.2.{{\left[ {\sqrt 3 } \right]}^2} + {{\left[ {\sqrt 3 } \right]}^3}}}\]

\[ = \sqrt {{{\left[ {2 - \sqrt 3 } \right]}^2}} - \sqrt[3]{{{{\left[ {2 + \sqrt 3 } \right]}^3}}}\\ = \left| {2 - \sqrt 3 } \right| - \left[ {2 + \sqrt 3 } \right]\]

\[ = 2 - \sqrt 3 - 2 - \sqrt 3 = - 2\sqrt 3 .\]

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