How many 3 letter passwords can be made using the letters A through Z if?
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If you're seeing this message, it means we're having trouble loading external resources on our website. Show If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked. There are 52 lowercase and uppercase letters and 10 digits, for a total of 62 characters. Assuming characters can be repeated, that is a total of $62^{10}$ passwords. However, if you are going to require at least one number, you have to then subtract all of the combinations that include no numbers, of which there are $52^{10}$, so the correct number of passwords is $62^{10} - 52^{10}$.  Arthur D. answered • 11/23/16 Tutor Mathematics Tutor With a Master's Degree In Mathematics About this tutor › About this tutor › these are permutations for example, ABC is different from CBA a) 26*26*26=17,576 b) 26*25*24=15,600 Upvote • 1 Downvote Add comment More Report Question 285006: how many different 3-letter passwords are possible if no letter can be repeated? Answer by toidayma(44) You can put this solution on YOUR website! How many 4 letter passwords can be made using the letters A through z if a repetition of letters is allowed?Answer and Explanation: There are 456,976 different 4-letter passwords that can be made using the letters a through z.
How many 3There are 2,600 different combinations of 3 letters in the alphabet. If you allow repeated characters, there are 3,276 different combinations.
How many 3The third letter can also be any one of 26, leading to 26 * 26 (or 26 ^ 2) combinations for each vowel. The total number of 3-letter combinations is then 5 * 26 * 26 = 3,380 combinations.
How many unique 3How many combinations of 3 letters can be made from 4 letters? If the letters are distinct and repetition is allowed then 4 * 4 * 4 = 4^3 = 64. If the letters are distinct and repetition is not allowed then 4 * 3 * 2 = 24.
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