What is the compound interest on rupees 2500 for 2 years at the rate of interest 4 percentage per annum?

Compound Interest: The future value (FV) of an investment of present value (PV) dollars earning interest at an annual rate of r compounded m times per year for a period of t years is:

FV = PV(1 + r/m)mtor

FV = PV(1 + i)n

where i = r/m is the interest per compounding period and n = mt is the number of compounding periods.

One may solve for the present value PV to obtain:

PV = FV/(1 + r/m)mt

Numerical Example: For 4-year investment of $20,000 earning 8.5% per year, with interest re-invested each month, the future value is

FV = PV(1 + r/m)mt   = 20,000(1 + 0.085/12)(12)(4)   = $28,065.30

Notice that the interest earned is $28,065.30 - $20,000 = $8,065.30 -- considerably more than the corresponding simple interest.

Effective Interest Rate: If money is invested at an annual rate r, compounded m times per year, the effective interest rate is:

reff = (1 + r/m)m - 1.

This is the interest rate that would give the same yield if compounded only once per year. In this context r is also called the nominal rate, and is often denoted as rnom.

Numerical Example: A CD paying 9.8% compounded monthly has a nominal rate of rnom = 0.098, and an effective rate of:

r eff =(1 + rnom /m)m   =   (1 + 0.098/12)12 - 1   =  0.1025.

Thus, we get an effective interest rate of 10.25%, since the compounding makes the CD paying 9.8% compounded monthly really pay 10.25% interest over the course of the year.

Mortgage Payments Components: Let where P = principal, r = interest rate per period, n = number of periods, k = number of payments, R = monthly payment, and D = debt balance after K payments, then

R = P r / [1 - (1 + r)-n]

and

D = P (1 + r)k - R [(1 + r)k - 1)/r]

Accelerating Mortgage Payments Components: Suppose one decides to pay more than the monthly payment, the question is how many months will it take until the mortgage is paid off? The answer is, the rounded-up, where:

n = log[x / (x � P r)] / log (1 + r)

where Log is the logarithm in any base, say 10, or e.

Future Value (FV) of an Annuity Components: Ler where R = payment, r = rate of interest, and n = number of payments, then

FV = [ R(1 + r)n - 1 ] / r

Future Value for an Increasing Annuity: It is an increasing annuity is an investment that is earning interest, and into which regular payments of a fixed amount are made. Suppose one makes a payment of R at the end of each compounding period into an investment with a present value of PV, paying interest at an annual rate of r compounded m times per year, then the future value after t years will be

FV = PV(1 + i)n + [ R ( (1 + i)n - 1 ) ] / i where i = r/m is the interest paid each period and n = m t is the total number of periods.

Numerical Example: You deposit $100 per month into an account that now contains $5,000 and earns 5% interest per year compounded monthly. After 10 years, the amount of money in the account is:

FV = PV(1 + i)n + [ R(1 + i)n - 1 ] / i =
5,000(1+0.05/12)120 + [100(1+0.05/12)120 - 1 ] / (0.05/12) = $23,763.28

Value of a Bond:

V is the sum of the value of the dividends and the final payment.

You may like to perform some sensitivity analysis for the "what-if" scenarios by entering different numerical value(s), to make your "good" strategic decision.

Replace the existing numerical example, with your own case-information, and then click one the Calculate.

A sum of money becomes Rs. 2,500 in 2 years and Rs. 3,000 in 3 years at a certain rate of compound interest. Find rate of interest per annum?

  1. 10% p.a.
  2. 15% p.a.
  3. 25% p.a.
  4. 20% p.a.

Answer (Detailed Solution Below)

Option 4 : 20% p.a.

Free

Delhi Forest Guard 2020: Full Mock Test

200 Questions 200 Marks 120 Mins

Given:

A sum of money becomes Rs. 2,500 in 2 years and Rs. 3,000 in 3 years at certain rate of compound interest.

Concepts used:

A = P × [1 + (R/100)]T

Where, A = Amount, P = Principal, R = Rate of interest, T = Time (in years)

Calculation:

A for 2 years = P × [1 + (R/100)]

⇒ Rs. 2,500 = P × [1 + (R/100)]2      ----(1) 

A for 4 years = P × [1 + (R/100)]

⇒ Rs. 3,000 = P × [1 + (R/100)]3      ----(2)  

Solving equations (1) and (2) by dividing eq (2) by eq(1),

 Rs. 3,000/Rs. 2,500 = P × [1 + (R/100)]3/P × [1 + (R/100)]2  

 3,000/2,500 =  [1 + (R/100)]

⇒ R/100 = 3,000/2500 – 1

⇒ R/100 = 500/2500

⇒ R = 500 × 100/2500

⇒ R = 20% p.a.

∴ Rate of interest is 20% p.a..

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Stay updated with the Quantitative Aptitude questions & answers with Testbook. Know more about Interest and ace the concept of Compound Interest.

What is the compound interest of rupees 2500 for 2 years at rate of interest 4 per annum?

= 2704 - 2500 = Rs. 204 C.I. - S.I.

What is the compound interest on Rs 2500 for 2?

2500 for 2 years at 12% p.a.? Compound interest in first year on a sum=Simple interest. So compound interest after 1 year=2500*1*12/100=Rs 300. For the next year Sum=2500+300=2800.

What will be the compound interest on a sum of Rs 2500?

[Solved] Compound interest accrued on a sum of Rs. 2500 is Rs. 749 at.

How much will ₹ 5000 amount in 2 years at compound interest if the rate for the successive years are 5% and 4% per year?

∴ Compound Interest =Rs 5724−Rs 5000=Rs 724.

What will be the compound interest on a sum of Rs 25000 after 2 years at the rate of 12% pa?

Rate of interest = 12% p.a. ∴ The compound interest is Rs. 10123.20.