Two dice are thrown together find the probability of getting the same number
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Show {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1),(3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)} When two dice are thrown together, all possible outcomes are(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) ∴ Total number of outcomes = 36 The favourable outcomes are (1, 1), (2, 2), (3, 3), (4, 4), (5, 5) and (6, 6). So, the number of favourable outcomes are 6. ∴ P(getting the same number on both dice) = \[\frac{\text{ Favourable number of outcomes }}{\text{ Total number of outcomes }} = \frac{6}{36} = \frac{1}{6}\] Solution : Total number of all possible outcomes = 36. What is the probability of getting same number when two dice is thrown together?` P(getting the same number on both dice) =`6/36 = 1/6`.
When two unbiased dice are rolled together the probability of getting both same outcomes is?The probability of both outcomes is equal i.e. 50% or 1/2. So, the probability of an event is Favorable outcomes/Total number of outcomes. It is denoted with the parenthesis i.e. P(Event). What is Sample Space?
When two dices are thrown what is the probability of not appearing the same number on the dices?P(not getting same numbers) =1−16 = 56. Q. Two dice are thrown simultaneously.
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